CHM ENG 140 Midterm: cheme140-fa2011-mt1-Iglesia-soln

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Consider an infinitesimal volume dv in the trough such that dv = l. x. dy = l. f(y). dy. We know that dy = . dt so we get dv = l. f(y). Problem 2: mixer #1: dof = 4 unknowns (m1, m2, m5, xa5) 2 balances = 2. Separator #1: dof = 4 unknowns (m2, m3, m4, xa5) - 2 balances = 2. Splitter: dof = 3 unknowns (m4, m5, xa5) - 1 balance = 2. Separator #2: dof = 3 unknowns (m7, m8, xa5) - 2 balances - 1 efficiency = 0. Mixer #2: dof = 3 unknowns (m3, m7, m9) - 1 balance = 2. Overall: dof = 3 unknowns (m1, m8, m9) - 2 balances = 1: separator #2 balance: Solve 3 equations for 3 unknowns: m7=22. 8kg/hr, m8=152. 2kg/hr, xa5=0. 26. Solve 2 equations for 2 unknowns: m1=184. 8kg/hr, m9=32. 6kg/hr. Solve 2 equations for 2 unknowns: m2=246. 4kg/hr, m5=61. 6kg/hr.

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