MAT-1120 Midterm: MATH 1120 App State Spring2009 Test1 answer key
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February 6th, 2009: (16 points) let f (x) = r x. 0 f (t) dt where the graph of f (t) is given below Form a: (a) f (0) = r 0. 0 f (t) dt = 0 and f (3) = r 3. When x = 2 we have y = f ( 2) = r 2. Also, y = f (x) = f (x) (by the fundamental theorem of calculus). m = f ( 2) = f ( 2) = 2. Therefore, the equation of the tangent is: (y 3) = 2(x ( 2)) so that y 3 = 2(x + 2) and thus Answer: y = 2x 1 f (t) dt = r 0. Form b: (a) f (0) = r 0 (b) f (0) = f (0) = 0 and f (5) = f (5) = 2 since f (x) = f (x) by the fundamental theorem of.
