MATA30H3 Midterm: MATA30 Midterm 2009 Fall Solutions

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16 Oct 2018
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2. (a) [ 3 marks] find all x satisfying: log2(x 3) + log2(x 1) = log2(2x + 19) solution : log2(x 3) + log2(x 1) = log2(2x + 19) log2(x 3)(x 1) = log2(2x + 19) 2log2(x 3)(x 1) = 2log2(2x+19) (x 3)(x 1) = (2x + 19) or x2 4x + 3 2x 19 = 0. thus we have: Simplify: x2 6x 16 = (x 8)(x + 2) = 0. However, log2(x 3) and log2(x 1) are not de ned if x = 2, therefore the only solution is x = 8. Let = arccos( 1 x2), then 1 x2 = cos where [0, ]. Since 1 x2 0, then !0, of the unit circle) with sides 1, x, 1 x2. We draw the triangle (in the rst quadrant (b) [ 4 marks] simplify: tan(arccos( 1 x2)). solution : since = arccos( 1 x2) then tan(arccos( 1 x2)) = tan = opp adj x.

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