MATH128 Quiz: MATH 128 Spring 2013 Assignment 5a.pdf
Document Summary
= [16 c1 + 8c2 + (16 c2 4)x 4x2] e4x. So 2 y 16 y + 32 y = 2{[16 c1 + 8c2 + (16 c2 4)x 4x2] e4x} 16{[4 c1 + c2 + (4 c2 )x x2]e4x} + 32[(c1 + c2x x2/4)e4x] = {(32 64 + 32) c1 + (16 16)c2 1 + [(32 64 + 32) c2 + ( 8 + 8)]x +( 8 +16 8) x2} e4x. Six points: 2 for a, 4 for b: solve the following using euler"s method. , y(2) = 1, step size 0. 2; find y(3). = 1 y x y x y y prime x delta. 3 0. 214286 0. 928571 y(3) = 0. 214286: y = 2xy + 2y, y(0) = 3, step size 0. 2; find y(1). x y prime x delta y. 1 27. 35318 109. 4127 y(1) = 27. 35318: y = y2(1 + 2x), y( 1) = 1, step size 0. 1; find y(0). x y prime x delta y.
