EE 301.3 Midterm: ee-301-2012-t1-midterm-2
Document Summary
2012 ee301 midterm ii solutions: law of biot-savart. A wire is bent into the shape of a regular hexagon with side a as shown below. Determine the magnetic eld vector at the centre of the hexagon (think! You might be interested to know that dx (x2 + c)3/2 = Because of the symmetry of a regular hexagon, each side produces the same magnetic. So we need calculate the vector for only one side and multiply the result by 6. The side at the top is a convenient choice. The vector is calculated using the law of biot-savart. The direction of the current is not speci ed, so i arbitrarily choose the counter-clockwise direction; then d~l = dx~ax. ~ar points from a bit of current at (x, 3a/2) to the origin; so. ~ar = x~ax ( 3a/2)~ay (x2 + 3a2/4)1/2 and r = (x2 + 3a2/4)1/2.
