CHEM 2770 Midterm: CHEM 2770 Ans-Dec-2008 Exam

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turquoisegnu128

31 Jan 2019

School

University of Manitoba

Department

Chemistry

Course

CHEM 2770

Professor

All

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C, a, d, b, e, d, b, d, b, a, b, b, e, d, d, b, c, d, b, c, b, b, e, a, b, a, d, a, a, c, e, d, e, b, b, d. Final exam answers dec 8, 2008: c. E: c, d, a, b, c, d, c, a, b, d, d. 35 the correct answer is c pyruvate decarboxylase and alcohol dehydrogenase . However the word alcohol was omitted from the answer. Those who chose answer c will receive 1 mark: 35 will be deleted from the exams of those who did not answer.

Related Questions

Please answer all the questions!

Nitrobenzene + Br_2/Fe + heat yields which product(s): a. m-bromonitrobenzene b. o-bromonitrobenzene c. p-bromonitrobenzene d. both b & c acetophenone + Br_2/Fe + heat yields which product(s): a. m-bromoacetophenone b. o- bromoacetophenone c. p- bromoacetophcnone d. both b & c cumene + HNO-3/H_2SO_4 + heat rightarrow a. m-nitrocumene b. o-(2-CH(CH_3)_2)benzenesulfonic acid c. o & p-nitrocumene d. something else! Which is the most acidic? a. cumene b. 4-nitroaniline c. 4-nitrophenol d. 4-methoxyphenol e. 4-methylphenol Which is the most basic? a. cumene b. 4-nitroaniline c. 4-methoxyaniline d. 4-chlorophenol c. 4-methylphenol nitrobenzene + acetyl chloride - AICl_3 rightarrow a. o-CH_3(C = O)NO_2benzene b. p-CH_3(C = O)NO_2 benzene c. p-CH_3 -(C = O)NO_2 benzene d. a & b e. no rxn benzene + 1. Br_2/FeBr_2 followed by 2. H_2SO_4/SO_3 rightarrow a. o-bromobenzenesulfonic acid b. p-bromobenzenesulfonic acid c. both a & b d m isomer e. no rxn benzene + 1.. H_2SO_4/SO_3 followed by 2. Br_2/FeBr_3 a. o-bromobenzenesulfonic acid b. p-bromobenzenesulfonic acid c. both a & b d m isomer e. no rxn benzene + acetyl chloride + AlCl_3 followed by Cl_2/AlCI_3/heat rightarrow a. o-chloroacetophenone b. p-chloroacetophenone c. m-chloroacetophenone d. a & b e. no reaction! p-methylanisole + HNO-3/H_2SO_4/heal rightarrow a. 2-nitro-4-methylanisole b. 3-nitro-4-methylanisole c. 3-nitro-5-methylanisole d. no rxn e. something else toluene + KMnO_4/OH^-/heat, then dilute acid quench, followed by HNO_3/H_2SO_4 rightarrow a. 3-nitrotoluene b. 4-nitrobenzenoic acid c. 3-nitrobenzoic acid d 2-nitrotoluene e. something else! a. 3-ehloroacetophenone b. 3-chlorophenol c. 4-chlorophenol d. 4-Chlorophenyl-l-ethanol e. a-d incorrect toluence + NBS/light, followed by NBS /light (repeat reaction a total of 3 times), then HNO_3/H_2SO_4 rightarrow a. 3-NO_2(Ph)CBr_3 b. 4-NO_2(Ph)CBr_3 c. 4-nitrotoluene d. 4-nitro-1, 3, 5-tribromobenzene e. a-d incorrect aniline + NaNO_2/HCI/zero degrees, then CuCN rightarrow a. benzonitrile b 2-cyanoaniline c. 4-cyancaniline d. both b & c e. 3-chloroaniline aniline + NaNO_2/HCI/zero degrees, then Cul a. 4-iodoaniline b. 4-nitroiodobenzene c. iodobenzene d. both a & b. e. something else! Do the following text problems: 1, 2., 3, 4, 5, 6, 7, 10, 11, 13, 14, 15, 17, 18, 23, 26, 28, 29, 30, 31, 36, 38, 39, 40, 42, 43, 45, 46, 48, 49, 50, 51, 55, 56, 61, 62

Give It Some Thought 6.16

Valence electron configurations of the elements.

Part A

The elements Ni, Pd, and Pt are all in the same group. By examining the electron configurations for these elements in the following figure, what can you conclude about the relative energies of the nd and (n+1)s orbitals for this group?

nd > (n+1)s

nd < (n+1)s

nd = (n+1)s

It is impossible to conclude.

Make a small table of the K_{\alpha } values from table 9.1 (included below), the K_{\alpha }(calc) value and the corrected value K_{\alpha }^{*} (calc) along with the \lambda_{K_{\alpha }} value from the experimental value and the value calculated from K_{\alpha }^{*} (calc) energy for the following elements: B, Na, Cl, Fe, and Ag. (note this is college upper level physical chemistry; I expect a full answer)

CHEM 2770 Midterm: CHEM 2770 Ans-Dec-2008 Exam

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