MBG 2040 Study Guide - Midterm Guide: Centimorgan, Lambda Phage, Recombinant Dna
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Which of these statements is incorrect?
Syntenic genes are located on the same chromosome. |
Independent assortment results in recombinant chromosomes. |
You can reliably predict the relative genetic distance fromgenesâ physical distance on a chromosome. |
Linked genes are always syntenic. |
What is the relative genetic distance between two linked genesif the recombination frequency is 0.49?
0.49 cM |
4.9 cM |
49 cM |
490 cM |
What statement best explains the distortion in Mendelian ratiosobserved by Bateson & Punnett in 1905? (Reminder: they found anoverrepresentation of F2 offspring showing both dominant orrecessive phenotypes, and an underrepresentation of offspringdisplaying one dominant and one recessive phenotype)
Human error: they should have been more careful about theirexperimental setup. |
Gene linkage: Genes for flower color and pollen shape arephysically close on the same chromosome, leading to a breakdown inthe independent assortment of the alleles for these traits. |
Chromosome crossover: Homologous recombination of twochromatids during meiosis caused the alleles to shuffle, resultingin a breakdown of the independent assortment of the alleles forthose genes. |
Random variation: No two situations are alike. In finitepopulations, you are going to get some variation across a mean. |
When determining the relative genetic distance between twogenes, why is dihybrid back-cross preferable over traditionaldihybrid cross?
9:3:3:1 phenotypic ratio is easier to work with than 1:1:1:1ratio. |
Genotypes of the offspring can be determined based on theirphenotype. |
If the genes are independently assorted, the dihybrid back-crosswould result in only 2 genotypes in the F1 generation. |
B and C |
Why do we map genes?
To understand how genes interact with each other |
Comparative genomics analysis |
To determine the genotype of an organism |
All of the above |
Hemoglobin and Fitness Instructions Directions: Neutral Evolution
1. Obtain 20 beans of two different colors (e.g., white and red). Count out 16 white and 4 red beans. The white beans represent the Hn allele and the red beans represent the Hs allele. This is the genetic makeup of your starting population. (Note: You can use any objects that can readily be categorized into two groups, such as coins, colored rocks, or paper clips.)
2.Calculate the frequency of both alleles [f(Hn) and f(Hs)] and record them in Table 1. In our experiment frequency is a measure of how many copies of a given allele exist in the gene pool (i.e., a proportion). Use decimal values. â¨
3.Arrange the beans into pairs. These pairs represent the genotype of each of 10 individuals in the population. Record the number of individuals with each genotype [f(Hn Hn), f(Hn Hs), and f(HsHs)] in Table 1. â¨
4.Now imagine that the individuals are living and reproducing with each individual reproducing at the same rate (i.e., all individuals produce two copies of each of their alleles into the next generation). Obtain enough beans to represent the next generationâ the offspring generationâand then let the parental generation âdieâ. â¨
5.Calculate the frequency of each allele in the offspring generation and record it in Table 1. â¨
Answer the questions that follow in Table 1. â¨
Table 1
f(HnHn) | f(HnHs) | f(HsHs) | f(Hn) | f(Hs) | |
oiginal generation | |||||
offspring generation |
Answer the following questions to help you understand the exercise:
What happened to the frequency of the common allele? â¨
What happened to the frequency of the rare allele? â¨
What happened to the frequency of the common and rare alleles when the starting frequencies were different from yours
What happens to allele frequencies from one generation to the next if there are no evolutionary forces acting on the population? â¨