MAAE 2300 Midterm: Exam-MAAE2300-2006Fall(SAMPLE)

• School: Carleton University
• Department: Mechanical and Aerospace Engineering
• Course: MAAE 2300
• Professor: All

Document Summary

There is no net contribution due to the free surface pressure ps since it is balanced by patm acting on the back side of the gate. Q = 0. 491 m3/s (a) vout = 12. 7 m/s. For parts (b) to (d) a value of vout = 15 m/s was to be used. Solved as an example in lectures. (a) 0. 75 mm (b) 0. 31 oc (c) 149 m. 3. (a) fh = 3. 521 x 106 n at 16. 987 m from free surface. (b) fh = 2. 825 x 106 n. H = 40. 9 m (a) q = 64. 9 m3/s (b) f = 760,000 n. = 30. 65 kw (i) increased (ii) f = 144. 3 n (in tension) My = 148 ft-lbf (a) fx = 98. 7 lbf (b) 0fan = 65. 8% N = 49. 6 rpm (a) )p12 = 50580 pa (b) q = 18. 1 m3/hr oil is flowing upward. 1 sheet 8 1/2 x 11, both sides, any non-transmitting calculator.