Find the equation of the plane in 𝑥𝑦𝑧���-space through the point 𝑃=(4,5,3)�=(4,5,3) and perpendicular to the vector 𝐧=(4,5,4)�=(4,5,4).

Find the equation of the plane in xyz-space through the point P = (4, 5, 3) and perpendicular to the vector n = (2, 1, 1). z =

Please write clearly process: Find the equation of the plane passing through the point (2, 0, 1) and perpendicular to the line with equations x = 3t, y = 2-t, z = 3 + 4t

Find an equation of the plane through the point (5 ,-5 ,5 ) and perpendicular to the vector ( -5 ,-2 ,0 ). Do this problem in the standard way or WebWork may not recognize a correct answer.