Torque can be calculated by multiplying the force (N) applied at  90∘90∘ to the lever arm at a distance (mm) from the pivot point (point of rotation), the compound SI unit for the torque is N⋅mN⋅m. If the force (at 90∘90∘ to the lever arm) applied is 15 N15 N and it is applied at 2.0 m2.0 m from the pivot point (point of rotation), what is the torque on the lever?

Table 1: Applied Force Required to Slide Cup

Questions:

1. What happened toyour applied force F_app as you decreased the amount ofwater in the cup?

2. Assume the mass tobe exactly equal to the mass of water. Calculate the normal force(F_N) for 300 g, 150 g, and 100 g. Use these values tocompute the ratio of the Applied Force (F_app) to theNormal Force (F_n). Place these values in the rightmostcolumn of Table 1.

What do these last two columns represent? What is theratio of the normal forces F₁ / F₃₀₀? Comparethis to your values for F₂/ F₁₅₀, andF₃/F₁₀₀. What can you concludeabout the ratio between the Force Normal and the ForceFriction?

F_N= mg
F_{N (300 g)} = _________kg

The potential energy (bonding energy), U, of two atoms at a distance, r, apart is given by

U= (-A/r^2)+(B/r^10)

If a stable molecule forms at a separation distance of 0.3 nm with a bond energy of -4eV, calculate A and B. Also find the force that must be applied to break the bond and the separation distance at which the bond will break.

I can't figure this one out.