Determine how much lead iodide (in grams) can be formed from 115g of lead nitrate and 265g of potassium iodide? Which is the limiting reactant?

a. Write a balance chemical equation for the reaction between aqueous lead(II)nitrate and aqueous potassium iodide to produce solid lead(II)iodide and aqueous potassium nitrate.

b. Calculate the grams of lead(II) iodide that can be produced from 75.00 grams of potassium iodide

Lead (II) nitrate reacts with potassium iodide to form lead (II) iodide and potassium nitrate. How do you write the balanced equation for this?

Determine the limiting reactant in each of the following reactions. Circle (Just label) the formula for the limiting reactant in each problem. Write the balanced equation and show all of your work. a. 3.50 mol of zinc reacts with 4.25 mol of silver nitrate. b. 10.6 mol of chlorine is added to 12.5 mol of potassium Iodide.PLEASE EXPLAIN THOROUGHLY