A solenoid consists of N = 110 turns of wire length d= 6 cm and cross-sectional area A = 3 cm2. Assume that the magnetic field inside the solenoid and ignore end effects.
(a) Write an equation for the magnetic field B produced by the solenoid. Express the answer in terms of the current through the coil I, the number of turns N, length of the coil d, and permeability of free space .
(b) Using the equation for the magnetic field determined in part (a), calculated the magnetic flux, in webers, through a single loop of the solenoid with a current of I = 1.9 A. The coil is d = 6 cm long and has a cross-sectional area of 3 cm2 and consists of 110 turns.
(c) The self inductance related the magnetic flux linkage to the current through the coil. Calculate the self inductance L in units of . THe coil is d = 6 cm long and has a cross-sectional area A = 3 cm2 and consists of N =110 turns.
