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The vector position of a 3.50-g particle moving in the XY plane varies in time according to r → 1 = ( 3 i ^ + 3 j ^ ) t + 2 j ^ t 2, where t is in seconds and r is in cm. At the same time, the vector position of a 5.50 g particle varies as r2 = 3i-2it^2-6jt. At t= 2.5s determine the net force exerted on the two-particle system.

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Uttam Saikia
Uttam SaikiaLv10
18 Nov 2020

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