The vector position of a particle varies in time according to the expression .

(a) Find an expression for the velocity of the particle as a function of time.

(b) Determine the acceleration of the particle as a function of time.

(c) Calculate the particle’s position and velocity at t = 1.00 s.

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Analyn TolentinoLv10

3 Jan 2021

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Related questions

The vector position of a 3.50-g particle moving in the xy plane varies in time according to , where t is in seconds and is in centimeters. At the same time, the vector position of a 5.50-g particle varies as . At t=2.50 s, determine

(a) the vector position of the center of mass of the system

(b) the linear momentum of the system

(d) the acceleration of the center of mass

(e) the net force exerted on the two-particle system

silverdonkey29

5. a particle starts from the origin with velocity 3j at t=0 and itmoves to the xy plane with acceleration a(t)=3tj +1i
a. determine the vector velocity pf the particle as a function oftime.
b. determine the position of the particle as a function of time.

The vector position of a 3.50-g particle moving in the XY plane varies in time according to it, r₁= (3i + 3j)t + 2jt², where t is in seconds and it is in centimeters. At the same time, the vector position of a 5.50 g particle varies as r₂ = 3i — 2jt² — 6jt. At t= 2.50 s,

determine

(a) the vector position of the center of mass of the system,

(b) the linear momentum of the system,

(d) the acceleration of the center of mass, and

(e) the net force exerted on the two-particle system.