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A parallel-plate capacitor with an air gap has capacitance C0. It is connected to a battery with potential V0 that gives it charge Q0 and stored energy U0. After the capacitor is disconnected from the battery, a dielectric with constant κ = 3 is inserted into the air gap, completely filling it. In terms of the initial values, find the new capacitance C, charge Q, potential V, and stored energy U.

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Tauseef Shaikh
Tauseef ShaikhLv10
21 Nov 2020

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