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6 Oct 2020
Because of Earth’s rotation about its axis, a point on the equator has a centripetal acceleration of 0.034 0 m/s2, whereas a point at the poles has no centripetal acceleration, Show that, at the equator, the gravitational force on an object (the object’s true weight) must exceed the object’s apparent weight.
Because of Earth’s rotation about its axis, a point on the equator has a centripetal acceleration of 0.034 0 m/s2, whereas a point at the poles has no centripetal acceleration, Show that, at the equator, the gravitational force on an object (the object’s true weight) must exceed the object’s apparent weight.
Ankit LalLv10
27 Nov 2020
