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The electrons in the beam of a television tube have a kinetic energy of  . Initially, the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down, toward the surface of the earth, and has a magnitude of .

(a) In what direction are the electrons deflected by this field component?





(b) What is the magnitude of the acceleration of an electron in part (a)?

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Priyanka
PriyankaLv10
21 Mar 2021

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Each of the electrons in the beam of a televisiontube has akinetic energy of 15.0 keV. The tube is oriented so thattheelectrons move horizontally from north to south. Theverticalcomponent of Earth's magnetic field points down and has amagnitudeof 45.0 μT. (Ignore the northward component ofEarth'sfield.)
Part A: In what direction will the electron beam deflect?
A) north
B) east
C) up
D) west
E) down
F) south
Part B:
Calculate the acceleration of a single electron due totheEarth's magnetic field.

Part C:
How far will the beam deflect if it moves a distance of 20.0 cmtothe south through the television tube?
Each of the electrons in the beam of a televisiontube has akinetic energy of 15.0 keV. The tube is oriented so thattheelectrons move horizontally from north to south. Theverticalcomponent of Earth's magnetic field points down and has amagnitudeof 45.0 μT. (Ignore the northward component ofEarth'sfield.)
Part A: In what direction will the electron beam deflect?
A) north
B) east
C) up
D) west
E) down
F) south

Part B:

Calculate the acceleration of a single electron due totheEarth's magnetic field.

Part C:
How far will the beam deflect if it moves a distance of 20.0 cmtothe south through the television tube?
An accelerating voltage of 2.50*103 V is applied to an electron gun, producing a beam of electrons originally traveling horizontally north in a vacuum toward the center of a viewing screen 35.0 cm away. What are (a) the magnitude and (b) the direction of the deflection on the screen caused by the Earth's gravitational field? What are (c) the magnitude and (d) the direction of the deflection on the screen caused by the vertical component of the Earth's magnetic field, taken as 20.0 uT down? (e) Does an electron in this vertical magnetic field move as a projectile, with constant vector acceleration perpendicular to a constant northward component of velocity? (f) Is it a good approximation to assume it has this projectile motion? Explain. 

 

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