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In exercise physiology studies, it is sometimes important to determine the location of a person's center of gravity. This can be done with the arrangement shown in the figure. A light plank rests on two scales that read and . The scales are separated by a distance of . How far from the woman's feet is her center of gravity?

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Sumant
SumantLv10
26 Mar 2021

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Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Many of the elements in horizontal-bar exercises can be modeled byrepresenting the gymnast by four segments consisting of arms, torso(including the head), thighs, and lower legs, as shown in Figure(a). Inertial parameters for a particular gymnast are asfollows:
Segment Mass (kg) Length (m) rcg (m) I (kg-m2)
Arms 6.87 0.577 0.239 0.205
Torso 33.90 0.601 0.337 1.61
Thighs 12.93 0.374 0.151 0.173
Legs 7.54 0.227 0.164

Note that in Figure (a) rcg is the distance to the center ofgravity measured from the joint closest to the bar and the massesfor the arms, thighs, and legs include both appendages. I is themoment of inertia of each segment about its center of gravity.Determine the distance from the bar to the center of gravity of thegymnast for the two positions shown in Figures (b) and (c). (Ineach case, take the positive direction for distances to run fromthe bar toward the location of the head.)
Figure (b) m
Figure (c) m


I need figure c he is shown with the bar at his torso leaning overit

Many of the elements in horizontal-bar exercises can be modeled byrepresenting the gymnast by four segments consisting of arms, torso(including the head), thighs, and lower legs, as shown in Figure(a). Inertial parameters for a particular gymnast are asfollows:
Segment Mass (kg) Length (m) rcg (m) I (kg-m2)
Arms 6.87 0.577 0.239 0.205
Torso 33.90 0.601 0.337 1.61
Thighs 12.93 0.374 0.151 0.173
Legs 7.54 - 0.227 0.164

Note that in Figure (a) rcg is the distance to the center ofgravity measured from the joint closest to the bar and the massesfor the arms, thighs, and legs include both appendages. I is themoment of inertia of each segment about its center of gravity.Determine the distance from the bar to the center of gravity of thegymnast for the two positions shown in Figures (b) and (c). (Ineach case, take the positive direction for distances to run fromthe bar toward the location of the head.)
Figure (b) m
Figure (c) m


I need figure c he is shown with the bar at his torso leaning overit

11.63 - BIO Downward-Facing Dog. The yoga exercise "Downward-Facing Dog” requires stretching your hands straight out above your head and bending down to lean against the floor. This exercise is performed by a 750-N person as shown in Fig. P11.63. When he bends his body at the hip to a 90° angle between his legs and trunk, his legs, trunk, head, and arms have the dimensions indicated. Furthermore, his legs and feet weigh a total of 277 N, and their center of mass is 41 cm from his hip, measured along his legs. The person's trunk, head, and arms weigh 473 N, and their center of gravity is 65 cm from his hip, measured along the upper body. (a) Find the normal force that the floor exerts on each foot and on each hand, assuming that the person does not favor either hand or either foot. (b) Find the friction force on each foot and on each hand, assuming that it is the same on both feet and on both hands (but not necessarily the same on the feet as on the hands). (Hint: First treat his entire body as a system; then isolate his legs (or his upper body).] Figure P11.63 90 cm 60 cm

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