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27 Nov 2019
The length of a 60 W, 240 ohms light bulb filament is 60 cm.
1) If the potential difference across the filament is 120 W, whatis the strength of the electric field inside the filament? E =V/m
2) Suppose the length of the bulb's filament were doubled withoutchanging its diameter or the potential difference across it. Whatwould the electric field strength be in this case? E = V/m
3) Remembering that the current in the filament is proportional tothe electric field, what is the current in the filament followingthe doubling of its length? I = A
4) What is the resistance of the filament following the doubling ofits length? R = ohms
The length of a 60 W, 240 ohms light bulb filament is 60 cm.
1) If the potential difference across the filament is 120 W, whatis the strength of the electric field inside the filament? E =V/m
2) Suppose the length of the bulb's filament were doubled withoutchanging its diameter or the potential difference across it. Whatwould the electric field strength be in this case? E = V/m
3) Remembering that the current in the filament is proportional tothe electric field, what is the current in the filament followingthe doubling of its length? I = A
4) What is the resistance of the filament following the doubling ofits length? R = ohms
Trinidad TremblayLv2
18 Oct 2019
