Question

<p>In the figure, four particles are fixed along an x axis,separated by distances d = 7.00 cm. The charges are q1 = +1e, q2 =-e, q3 = +e, and q4 = +4e, with e = 1.60 10-19 C. In unit-vectornotation, where right is the + direction, what is the netelectrostatic force on each particle below due to the otherparticles?<br /><br />I am very very confused by thisproblem.</p>
<p>I figured that you would set this up like but am unsure ofthe q2 value since its Negative. I believe it only refers todirection.</p>
<p>&#160;</p>
<p>F1 = F(12) + (F13) + F(14)&#160;</p>
<p>F(12) = (8.99*10^9)(1.6*10^-19)(1.6*10^-19) /.07^2</p>
<p>F(13) = (8.99*10^9)(1.6*10^-19)(1.6*10^-19) /.14^2</p>
<p>F(14) = (8.99*10^9)(1.6*10^-19)(6.4*10*-19) /.21^2</p>
<p>&#160;</p>
<p>Also it is wanting me to answer in Vector Notation?HUH</p>
<p>&#160;</p>
<p>&#160;</p>