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27 Nov 2019
the acceleration of a marble in a certain fluid is proportional tothe speed of the marble squared given by a=av^2 where v>0 m/sand a=-2.15m^-1, if the marble enters this fluid with a speed of2.1 m/s, how long will it take before the marble's speed is reducedto half of 16s initial value?
a=a*v^2
dv/dt=a*v^2
v0=2.1m/2 (t=0)
Vt(t=?)=V0/2
dv/dt=-2.15
dv=-2.15v^2dt
the acceleration of a marble in a certain fluid is proportional tothe speed of the marble squared given by a=av^2 where v>0 m/sand a=-2.15m^-1, if the marble enters this fluid with a speed of2.1 m/s, how long will it take before the marble's speed is reducedto half of 16s initial value?
a=a*v^2
dv/dt=a*v^2
v0=2.1m/2 (t=0)
Vt(t=?)=V0/2
dv/dt=-2.15
dv=-2.15v^2dt