Question

1. A particle has a charge of +1.5μC and moves from point A topoint B, a distance of 0.25m. The particle experiences a constantelectric force, and its motion is along the line of action of theforce. The difference between the particle's electric potentialenergy at A and B is EPE(a) - EPE(b) = +6.00 x 10^-4 J.

(a) Find the magnitude and direction of the electric force thatacts on the particle.

magnitude __________N direction____________

(b) Find the magnitude and direction of the electric field thatthe particle experiences.

magnitude___________N/C direction___________

2. A positive charge +q1 is located to the left of a negativecharge -q2. On a line passing through the two charges, there aretwo places where the total potential is zero. The first place isbetween the charges and is 1.0 cm to the left of the negativecharge. the second place is 5.2 cm to the right of the negativecharge.

(a) What is the distance between the charges?

___________cm

(b) Find q1/q2, the ratio of the magnitudes of the charges.

q1/q2 = ____________