Q:Aperson rides up a lift to a mountain top, but the person'searsfail to "pop" - that is, the pressure of the inner ear doesNOTequalize with the outside atmosphere. The radius of each eardrumis0.4 cm. The pressure of the atmosphere drops from 1.01 x 10^5 Paatthe bottom of the lift to 0.988 x 10^5 Pa at the top. What isthepressure on the inner ear at the top of the mountain?
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Hi, Iamconfused as to what formula (or formulasâ¦) to use forthisproblem. I know Pressure is equal to Force over Area, but sinceIdidn't know for either side I don't know if I can use that. Ialsoknow that F1 / A1 = F2 / A2, but again I'm not sure howtocalculate force or if I even need to calculate force.
Cansomeone show a step by step solution to solve this?
I knowtheanswer is 1.2 x 10^3 Paâ¦but I can't arrive at this.Thanks forreading.
Q:Aperson rides up a lift to a mountain top, but the person'searsfail to "pop" - that is, the pressure of the inner ear doesNOTequalize with the outside atmosphere. The radius of each eardrumis0.4 cm. The pressure of the atmosphere drops from 1.01 x 10^5 Paatthe bottom of the lift to 0.988 x 10^5 Pa at the top. What isthepressure on the inner ear at the top of the mountain?
--
Hi, Iamconfused as to what formula (or formulasâ¦) to use forthisproblem. I know Pressure is equal to Force over Area, but sinceIdidn't know for either side I don't know if I can use that. Ialsoknow that F1 / A1 = F2 / A2, but again I'm not sure howtocalculate force or if I even need to calculate force.
Cansomeone show a step by step solution to solve this?
I knowtheanswer is 1.2 x 10^3 Paâ¦but I can't arrive at this.Thanks forreading.
