Log in
Physics
1
answer
0
watching
73
views
26 Nov 2019

In exercise physiology studies, it is sometimes importanttodetermine the location of a person's center of gravity. This canbedone with the arrangement shown in the figure below. A lightplankrests on two scales that readFg1 =360 NandFg2 = 320 N. The scales areseparated by a distance of2.00 m. How far from the woman's feet isher center of gravity?
1 m

Watch
1
answer
0
watching
73
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Jarrod Robel
Jarrod RobelLv2
21 Nov 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share

Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A gravity board is a convenient and quick way to determine thelocation of the center of gravity of a person. It consists of ahorizontal board supported by a fulcrum at one end and a scale atthe other end. To demonstrate this in class, your physics professorcalls on you to lie horizontally on the board with the top of yourhead directly above the fulcrum point as shown in the figure. Thefulcrum is 2.00 m from the scale. In preparation for thisexperiment, you had accurately weighed yourself and determined yourmass to be 90.0 kg. When you are at rest on the gravity board, thescale advances 275 N beyond its reading when the board is there byitself. Use this data to determine the location of your center ofgravity relative to the top of your head.
1 m

Many of the elements in horizontal-bar exercises can be modeled byrepresenting the gymnast by four segments consisting of arms, torso(including the head), thighs, and lower legs, as shown in Figure(a). Inertial parameters for a particular gymnast are asfollows:
Segment Mass (kg) Length (m) rcg (m) I (kg-m2)
Arms 6.87 0.577 0.239 0.205
Torso 33.90 0.601 0.337 1.61
Thighs 12.93 0.374 0.151 0.173
Legs 7.54 0.227 0.164

Note that in Figure (a) rcg is the distance to the center ofgravity measured from the joint closest to the bar and the massesfor the arms, thighs, and legs include both appendages. I is themoment of inertia of each segment about its center of gravity.Determine the distance from the bar to the center of gravity of thegymnast for the two positions shown in Figures (b) and (c). (Ineach case, take the positive direction for distances to run fromthe bar toward the location of the head.)
Figure (b) m
Figure (c) m


I need figure c he is shown with the bar at his torso leaning overit

Many of the elements in horizontal-bar exercises can be modeled byrepresenting the gymnast by four segments consisting of arms, torso(including the head), thighs, and lower legs, as shown in Figure(a). Inertial parameters for a particular gymnast are asfollows:
Segment Mass (kg) Length (m) rcg (m) I (kg-m2)
Arms 6.87 0.577 0.239 0.205
Torso 33.90 0.601 0.337 1.61
Thighs 12.93 0.374 0.151 0.173
Legs 7.54 - 0.227 0.164

Note that in Figure (a) rcg is the distance to the center ofgravity measured from the joint closest to the bar and the massesfor the arms, thighs, and legs include both appendages. I is themoment of inertia of each segment about its center of gravity.Determine the distance from the bar to the center of gravity of thegymnast for the two positions shown in Figures (b) and (c). (Ineach case, take the positive direction for distances to run fromthe bar toward the location of the head.)
Figure (b) m
Figure (c) m


I need figure c he is shown with the bar at his torso leaning overit

Weekly leaderboard

Home
Homework Help 3,900,000
Physics 110,000
Start filling in the gaps now
Log in