An object is thrown vertically upward and has a speed of 18 m/swhen it reaches three fifths of its maximum height above the launchpoint. Determine its maximum height.

dx=18t+-4.9t^2

3.67=t

v=18-9.8t
-18/-9.8= 1.836

answer

watching

101

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Deanna HettingerLv2

11 Jan 2019

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Related questions

A rock is thrown vertically upward from ground level at timet = 0. At time t = 1.4 s it passes the top of atall tower, and 1.2 s later it reaches its maximum height. What isthe height (in m) of the tower?

A baseball is thrown vertically upward. The mass of the baseball is m, and its initial speed is v_i. . What is the momentum of the baseball at its maximum height?

yellowreindeer728

A rock is thrown vertically upward from ground level at time t = 0. At t = 1.5 s it passes the top of a tall tower, and 1.0 s later it reaches its maximum height. What is the height of the tower?