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23 Nov 2019

Im trying to solve this question, and i dont know whether to usesimple math or try to use calculus.

Three digital clocks A, B, and C run at different rates and do nothave simultaneous readings of zero. The Figure shows simultaneousreadings on pairs of the clocks for four occasions. (At theearliest occasion, for example, B reads 25.0 s and C reads 92.0 s.)If two events are 500 s apart on clock A, how far apart are they on(a) clock B and (b) clock C? (c) When clock A reads 410 s, whatdoes clock B read? (d) When clock C reads 9 s, what does clock Bread? (Assume negative readings for prezero times.)
-----------------312-----------------------512---A
-25-------------125----------200---- ----290---B
-92---------------------------142----------------C


So i figured out A and B using simple math ratio's.

A- (200/165) x (500/?). I know that 200/165 is where the clocks aresync and i can just multiply crossmultiply etc, and i get606.

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Jarrod Robel
Jarrod RobelLv2
30 Aug 2019

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