I have a solution for 22.55 in Physics: Principles withApplications (6th) by Giancoli. There is no problem 55 listed inchapter 22, so how can I make the submission? I also have asolution for 22.54. The one given is not for problem 54.
I have a solution for 22.55 in Physics: Principles withApplications (6th) by Giancoli. There is no problem 55 listed inchapter 22, so how can I make the submission? I also have asolution for 22.54. The one given is not for problem 54.
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Calculus Based Physics | Physics For Scientists And Engineers withModern Physics (7th)by Serway, Jewett | 46 | 55AP | 6/10/2010 at 11:55:00 AM |
| Question Details: Ans. given below isnotadequate. problem 55 ch 46 page 1390 asks for "the upper limit thattheobservation sets on the mass of a neutrino". Obs. was a supernova 170 000 ly away. 8 neutrinos in 6s, (energies betw. 8 MeV and 40 MeV) and 11 n's in 13 s ( 10 MeV n. needs 10 s more than photontotravel this distance) The expert solution does not give this ans. It only converts light years to seconds! The book gives the ans. as " 19 eV/(c squared)" Please explain this ans. Brian. |
Response Details:
19eV is energy in electron volts. 1 electron volt is1.6e-19Joules, so for very small energies it is more convenient touse theelectron volt rather than Joules.
From Einstein's equation e=mc*c, the solution you gave hasjustrearranged this to m=e/c*c
Was this what you needed clarification on?
My Response Details:
That is true but does this give the ans. 19 eV/c*c ?
m = e/c*c
m= 1.6 e -19/c*c but this is not = 19??
Sorry this is wrong. I have confused e for energy with eforelectronic charge.
Energy was 10 MeV,so m = 10 e^6/c*c.
This is still not = 19/c*c.
Please show how to get 19/c*c.
Brian.