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23 Nov 2019

A 3.0-kg block slides along a frictionless tabletop at 8.0 m/s toward a second block (at rest) of mass 4.5kg . A coil spring, which obeys Hooke's law and has spring constant k = 890 N/m , is attached to the second block in such a way that it will be compressed when struck by the moving block. A) What will be the maximum compression of the spring? B) What will be the final velocities after the collision? C) is this elastic collision? (Ignore the mass of the spring) will give A++

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A 2.2 kg block slides along a frictionless tabletop at 6.0 m/stoward a second block (at rest) of mass 5.1 kg. A coil spring,which obeys Hooke's law and has spring constant k = 870 N/m, isattached to the second block in such a way that it will becompressed when struck by the moving block, see the figure.



(a) What will be the maximum compression of the spring?
1 .252 m (got that right)

(b) What will be the final velocities of the blocks after thecollision? (Assume the initial direction of the 2.2 kg block ispositive.)
2.2 kg block
m/s
5.1 kg block
m/s
(c) Is the collision elastic? Ignore the mass of the spring.(Compare energy values to the nearest joule.)


4

yes no



Give the kinetic energy of the system before and after thecollision to justify your answer.
before
J
after
J


A block of mass m1 = 3.0 kg slides along a frictionless table with a velocity of +10 m/s. Directly in front of it, and moving with a velocity of +3.0 m/s, is a block of mass m2 = 5.0 kg. A massless spring with spring constant k = 1120 N/m is attached to the second block as in the figure below.(a) What is the velocity of the center of mass of the system? (b) During the collision, the spring is compressed by a maximum amount ?x. What is the value of ?x? (c) The blocks will eventually separate again. What are the velocities of the two blocks measured in the reference frame of the table, after they separate?

1. A woodblock of mass mw = 200 g is projected from the ground at a speed v0 = 35 m/s and at an angle θ0 = 50º. When at height h = 24 m the woodblock was hit by a bullet of mass mb = 25 g which was moving at vb = 220 m/s and at an angle θb = 70º. After the collision, the bullet embedded itself in the block and move together and land at point A on the ground. Then they
move on the ground that has a coefficient of kinetic friction µk = 0.5 and starts to compress a 
horizontal spring at point B. The distance between point A and B is 18 m and the spring constant k = 3×102 N/m. The right end of the spring is fixed, and all motions are confined in x-y plane.
(a) Was the collision between the woodblock and the bullet elastic or inelastic? 
Explain quantitively. (6 marks)
(b) Find the maximum height from the ground the block with the bullet reached. (2 marks)
(c) How far is point A from the launch point of the woodblock? (4 marks)
(d) Calculate the velocity at which the block-bullet system lands at point A. What will be the speed of it at point B?
(5 marks)
(e) Determine how much the spring will be compressed when the block-bullet system comes to a rest

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