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23 Nov 2019

A coin placed 30.6 cm from the center of a rotating, horizontalturntable slips when its speed is 49.3 cm/s.
(a) What force causes the centripetal acceleration when the coin isstationary relative to the turntable?
a)static friction
b)inertia
c)kinetic friction
d)centrifugal force
.

(b) What is the coefficient of static friction between coin andturntable?

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Deanna Hettinger
Deanna HettingerLv2
21 Oct 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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may you please help me with this too? thanks
A coin is placed 32 cmfrom the center of a horizontalturntable, initially at rest. Theturntable then begins to rotate.When the speed of the coin is 100cm/s (rotating at a constantrate), the coin just begins to slip.The acceleration of gravity is980 cm/s2 . What is the coefficientof static friction be-
tween the coin and the turntable?

Part A:
A coin placed on a turntable rotating at 38.7 rev/min will staythere if its center is placed no further than 7.2 cm from the axisof rotation. What is the maximum distance the center of the coincan be placed from the axis if the turntable rotates at 45.0rev/min?

Part B:
What is the coefficient of friction between the coin and turntable?

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