1
answer
0
watching
138
views
23 Nov 2019

two point charges are distanced d=47.5cm apart, they haveequal and opposite charge each with magnitude Q=6.11 µC. Thenegative charge is on the left, and the positive on the right. Anelectron (mass 9.11e-31kg, charge 1.6e-19C is placed halfwaybetween the charges.
a)The electric field at this point is?
b)The direction of the electric field is?
c)The force on the electron is?
To find a, I did E=F/q and got 2.69e19 N/C and it'swrong
for b, I chose to the right, toward the positive charge, andit's wrong
for c, I did F=Eq and I got 3.856e-14N and it's wrong
What am I doing wrong?

For unlimited access to Homework Help, a Homework+ subscription is required.

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in

Related textbook solutions

Related questions

Weekly leaderboard

Start filling in the gaps now
Log in