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A capacitor is a device having two electrodes that can be used to store electric charge. When a battery is attached to the capacitor, a positive charge moves to one electrode and an equal negative charge collects on the other. The capacitance of this system is defined as the ratio of the magnitude of the charge on either electrode to the voltage of the attached battery. Capacitance is measured in farads (coulombs per volt). A 1.5 volt D-cell battery is attached to a 2.2 picofarad capacitor. (a) Find the charge that appears on the positive electrode. (b) Find the charge that appears on the negative electrode. (c) Find the net charge of the entire capacitor.

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Hubert Koch
Hubert KochLv2
17 Oct 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

The SI unit of capacitance is a  derived unit is known as the farad (named after Michel faraday) One farad is defined as one coulomb per volt 1F=1C/1V write an equation that relates capacitance, charge, and potential this equation for a charge. one coulomb per volt: F=1C/1V. Based on the definition of the unit. write an equation that relates capacitance, charge, and potential. and then solve this equation for the charge. 

 

An engineer needs a 1.0 μF parallel-plate capacitor with a spacing of 0.050 mm of plates. She will use the capacitor in the design of a portable electronic device.

a. What would the area of the plates need to be to make this capacitor? Assume te  εo = 8.85 *10-12CNm). 

b. Discuss the practicality of this capacitor in the context of its intended use.

c. If the portable electronic device is designed to use a 1.5 V battery, what is the maximum charge the capacitor can store?

PART A What property of objects is best measured b

(a) What property of object is best measured by their capacitance?

  1. Ability to conduct electric current.
  2. Ability to distort an external electrostatic field
  3. Ability to store charge.

(b) Assume -q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric field E between the plates?

(c) What is the voltage between the plates of the capacitor?

(d) What is the capacitance of the capacitor?

(e) Consider an air filled charge capacitor. How can its capacitance be increased? 

 

To understand the meaning of capacitance and ways of calculating capacitance.

When a positive charge q is placed on a conductor that is insulated from ground, an electric field emanates from the conductor to ground, and the conductor will have a nonzero potential V relative to ground. If more charge is placed on the conductor, this voltage will increase proportionately. The ratio of charge to voltage is called the capacitance C of this conductor: C=q/V.

Capacitance is one of the central concepts in electrostatics, and specially constructed devices called capacitors are essential elements of electronic circuits. In a capacitor, a second conducting surface is placed near the first (they are often called electrodes), and the relevant voltage is the voltage between these two electrodes.

This tutorial is designed to help you understand capacitance by assisting you in calculating the capacitance of a parallel-plate capacitor, which consists of two plates each of area A separated by a small distanced with air or vacuum in between. In figuring out the capacitance of this configuration of conductors, it is important to keep in mind that the voltage difference is the line integral of the electric field between the plates.

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  1. Assume that charge -q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric field E between the plates?
  2. What is the voltage V between the plates of the capacitor?

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