An ideal spring obeys Hooke's law, F = kx. A mass of 0.50 kilogramhung vertically from this spring stretches the spring 0.075 meter.The value or the force constant for the spring is most nearly
0.33 N?/?m

0.66 N?/?m

6.6 N?/?m

33 N?/?m

66 N?/?m

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14 Feb 2019

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When a 2.90-kg object is hungvertically on a certain light springdescribed by Hooke's law, thespring stretches 2.76 cm.

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Hooke's law describes a certain light spring of unstressed length36.0 cm. When one end is attached to the top of a door frame and a6.60 kg object is hung from the other end, the length of the springis 41.50 cm.

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Hooke's law describes a certain light spring of unstretchedlength32.0 cm. When one end is attached tothe top of a door frame,and a 7.20-kgobject is hung from the other end, the length of thespring is42.50 cm.

(a) Find its spring constant.
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An ideal spring obeys Hooke's law, F = kx. A mass of 0.50 kilogramhung vertically from this spring stretches the spring 0.075 meter.The value or the force constant for the spring is most nearly
0.33 N?/?m

0.66 N?/?m

6.6 N?/?m

33 N?/?m

66 N?/?m

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Physics: Principles with Applications

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An ideal spring obeys Hooke's law, F = kx. A mass of 0.50 kilogramhung vertically from this spring stretches the spring 0.075 meter.The value or the force constant for the spring is most nearly0.33 N?/?m0.66 N?/?m6.6 N?/?m33 N?/?m66 N?/?m

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Related textbook solutions

Physics: Principles with Applications

Related questions

Weekly leaderboard

An ideal spring obeys Hooke's law, F = kx. A mass of 0.50 kilogramhung vertically from this spring stretches the spring 0.075 meter.The value or the force constant for the spring is most nearly
0.33 N?/?m

0.66 N?/?m

6.6 N?/?m

33 N?/?m

66 N?/?m