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23 Nov 2019
A square current loop lies flat in the x-y plane with its sidesparallel to the x and y axes. The side of the square is a. Thecurrent flowing in the loop is I, in the CCW direction as viewedfrom above. A uniform magnetic field B = B(i/sqrt(2) + k/sqrt(2) isapplied to the loop. (With B in the formula as Bo, i being i hatand k being k hat)
a) Find the magnetic force (magnitude and direction) on each sideof the loop. Check that the sum of the four forces equalszero.
b) Find the torque (magnitude and direction) on the current loop.
A square current loop lies flat in the x-y plane with its sidesparallel to the x and y axes. The side of the square is a. Thecurrent flowing in the loop is I, in the CCW direction as viewedfrom above. A uniform magnetic field B = B(i/sqrt(2) + k/sqrt(2) isapplied to the loop. (With B in the formula as Bo, i being i hatand k being k hat)
a) Find the magnetic force (magnitude and direction) on each sideof the loop. Check that the sum of the four forces equalszero.
b) Find the torque (magnitude and direction) on the current loop.
Jarrod RobelLv2
11 Apr 2019
