A capacitor is formed by two metal plates. The plates are squarewith width W on each side. The plates are separated by a distanced. A voltage V is applied across the two plates.
A dielectric is inserted between the two plates that extendsthrough the capacitance and occupies half of the volume between thetwo plates. The remaining volume between the plates is simply air.The relative dielectric constant of the material inserted is2.0.
a. Find the electric field intensity E and the electric fluxdensity D in each of the regions between the two plates.
b. Calculate the capacitance between the two plates.
c. Calculate the energy stored on the capacitor.
d. If the dielectric is removed so that only air remains betweenthe two plates, is the energy stored higher of lower than with thedielectric?
A capacitor is formed by two metal plates. The plates are squarewith width W on each side. The plates are separated by a distanced. A voltage V is applied across the two plates.
A dielectric is inserted between the two plates that extendsthrough the capacitance and occupies half of the volume between thetwo plates. The remaining volume between the plates is simply air.The relative dielectric constant of the material inserted is2.0.
a. Find the electric field intensity E and the electric fluxdensity D in each of the regions between the two plates.
b. Calculate the capacitance between the two plates.
c. Calculate the energy stored on the capacitor.
d. If the dielectric is removed so that only air remains betweenthe two plates, is the energy stored higher of lower than with thedielectric?
