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23 Nov 2019

A car is traveling at a rate of 18 feet per second when the brakesare applied. The position function for the car is given by s =–2.25t2 + 18t, where s is measured in feet and t is measured inseconds. Create a table showing the position, velocity, andacceleration for each given value of t.
t 0 1 2 3 4 5

s(t) _____ 15.75 27 _____ ______ 33.75

v(t) _____ 13.50 9 4.50 ______ ______

a(t) -4.50 -4.50 -4.50 -4.50 -4.50 -4.50


What can you conclude?
A) It takes 4 seconds for the car to stop, at which time it hastraveled 4.5 ft.
B) It takes 3 seconds for the car to stop, at which time it hastraveled 33.75 ft.
C) It takes 4 seconds for the car to stop, at which time it hastraveled 36 ft.
D) It takes 4 seconds for the car to stop, at which time it hastraveled 2.25 ft.
E) It takes 5 seconds for the car to stop, at which time it hastraveled 33.75 ft.
F) It takes 4 seconds for the car to stop, at which time it hastraveled 18 ft.

What equation did you use for v(t)? that is where I got stuck.

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Casey Durgan
Casey DurganLv2
1 Jan 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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