1
answer
0
watching
304
views
23 Nov 2019
The position of a simple harmonic oscillator is given byx(t)=(0.50m)cos(pi/3)t where t is in
seconds.
a)What is the maximum velocity of this oscillator?
b) What is the period of the oscillator?
Answer: a) 0.52 m/s, b) 6 sec
The position of a simple harmonic oscillator is given byx(t)=(0.50m)cos(pi/3)t where t is in
seconds.
a)What is the maximum velocity of this oscillator?
b) What is the period of the oscillator?
Answer: a) 0.52 m/s, b) 6 sec
Tod ThielLv2
16 Oct 2019
