How did you get the degrees for cosθ

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orchidrabbit535

The figure is an edge-on view of a 14 cm diameter circular loop rotating in a uniform 3.8×10^-2 T magnetic field. I solved part a by using

φ= B A cos θ = Bπr² cosθ = (3.8 x 10^-2) π (.07)2cos (0 degrees)= 5.8 x 10^-4 Wb and got correct answer,

but having trouble finding the right answer for part B. I used the same equation for part B and used cos (30)= got the wrong answer. Is there another equation for finding the answer with the other angles?

Part A What is the magnetic flux through the loop when is 0 degrees?

Express your answer to two significant figures and include the appropriate units.
=5.8×10⁻⁴ Wb
Correct

Part B What is the magnetic flux through the loop when is 30 degrees?
Express your answer to two significant figures and include the appropriate units.
=

Part C
What is the magnetic flux through the loop when is 60 degrees?
Express your answer to two significant figures and include the appropriate units.
=

Part D What is the magnetic flux through the loop when is 90 degrees?
Express your answer to two significant figures and include the appropriate units