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20 Nov 2019

A sculptor is sharpening a chisel on grindstone of radius 1.0 mthatis spinning with a constant angular speed of 2.0 rad/s.

What is the magnitude of the tangentialacceleration of apoint on the rim of the wheel?

 A)
zerom/s2

B)
2.0m/s2

C)
4.0m/s2

D)
0.5m/s2

E)
1.0m/s2

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19 Sep 2019
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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

hi,



i have 5 questions i need the
complete solutions with their final results. is there anyonecouldhelp
me, i would appreciate that.



1)
2600 rev/min is equivalent to which of the following?
1. 273 rad/s
2. 43.3 rad/s
3. 2600 rad/s
4. 60 rad/s


2)

A 0.30-m-radius automobile tire rotates how many rad afterstartingfrom rest and accelerating at a constant 2.0 rad/s2 over a5.0-sinterval?


3)

A Ferris wheel starts at rest and builds up to a final angularspeedof 0.70 rad/s while rotating through an angular displacementof 4.9rad. What is its average angular acceleration?


4)

A Ferris wheel, rotating initially at an angular speed of0.50rad/s, accelerates over a 7.0-s interval at a rate of 0.040rad/s2.What is its angular speed after this 7-s interval?


5)

A point on the rim of a 0.30-m-radius rotating wheel hasatangential speed of 4.0 m/s. What is the tangential speed ofapoint 0.20 m from the center of the same wheel?







thank you in advance

A wheel is rotating about an axis with constant angular acceleration 3 rad/s2. At different moments, its angular speed is -2 rad/s,o,+2 rad/s. For a point on the rim of the wheel, consider at these moments the magnitude of the tangential component of acceleration and the magnitude of the radial component of acceleration. Rank the following five items from largest to smallest:

a)  

b)  

c)  

d)  

e)  

In a Beams ultracentrifuge, a 19.5 cm long rotor is suspendedmagnetically in a vacuum. Since there is no mechanical connectionto the rotor, the only friction is the air resistance due to thefew air molecules in the vacuum. If the rotor is spinning with anangular speed of 4.8 105 rad/s and the driving force is turned off,its spinning slows down at an angular rate of 0.39 rad/s2.
(a) For a point at the end of the rotor, find the initialspeed.
answer is 0.936 e5 m/s

(b) For a point at the end of the rotor, find the tangentialacceleration component.
answer is 0.0761 m/s2

(c) For a point at the end of the rotor, find the maximum radialacceleration component.
answer is 4.49e+10m/s2

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