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14 Nov 2019
The figure below shows a plot of potential energy U versus position x of a 0.98 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) In the graphs, the potential energies are U1 = 10J, U2 = 25J, and U3 = 45J. The particle is released at x = 4.5 m with an initial speed of 9.5 m/s, headed in the negative x direction. If the particle can reach x = 1.0 m, what is its speed there, and if it cannot, what is its turning point? What are the magnitude and direction of the force on the particle as it begins to move to the left of x = 4.0 m? N in the direction. Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.5 m at speed 9.5 m/s. If the particle can reach x = 7.0 m, what is its speed there, and if it cannot, what is its turning point? What are the magnitude and direction of the force on the particle as it begins to move to the right of x = 5.0 m? N in the direction.
The figure below shows a plot of potential energy U versus position x of a 0.98 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) In the graphs, the potential energies are U1 = 10J, U2 = 25J, and U3 = 45J. The particle is released at x = 4.5 m with an initial speed of 9.5 m/s, headed in the negative x direction. If the particle can reach x = 1.0 m, what is its speed there, and if it cannot, what is its turning point? What are the magnitude and direction of the force on the particle as it begins to move to the left of x = 4.0 m? N in the direction. Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.5 m at speed 9.5 m/s. If the particle can reach x = 7.0 m, what is its speed there, and if it cannot, what is its turning point? What are the magnitude and direction of the force on the particle as it begins to move to the right of x = 5.0 m? N in the direction.
Elin HesselLv2
12 Apr 2019