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14 Nov 2019

Two particles of identical mass m and charge q aresuspended bymeans of uncharged threads of identical length L whosemasses arenegligible. Due to the forces present, each particle isin a stateof equilibrium. Due to the symmetry of theconfiguration, eachthread forms the angle (data) with the verticaldirection, asdepicted in the diagram. Standard gravity actsverticallydownward.

a) Let T denote the magnitude of the tension force inthethread and F denote the magnitude of the electrostaticforceexerted on a particle. By constructing a proper free-bodydiagramfor either particle, show that
sin(θ)*T= F, cos(θ)*T = mg
b)By combining these equations, show that
(sin(θ))^2*tan(θ)= (K_e*q^2)/(4*L^2*mg)
c) Assume that (θ) << 1 (radian), so thattan(θ) ˜sin(θ). Determine an approximate value forθ when
m = 5.0 g, q = 25 nC, and L = 120 cm. Express this value ofθin degrees.
d) Furthermore, in the case for which tan(θ) ˜sin(θ), showthat
x˜ ((2*K_e*q^2*L)/(mg))^(1/3)
Determine an approximate value for x based upon thedataprovided above.
Please provide step by step solutions please....

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Sixta Kovacek
Sixta KovacekLv2
6 Feb 2019

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