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10 Nov 2019

Three dimensions. Three point particles are fixed in place in anxyz coordinate system. Particle A, at the origin, has mass mA.Particle B, at xyz coordinates (2.00d, 1.00d, 2.00d), has mass2.00mA, and particle C, at coordinates (-1.00d, 2.00d, -3.00d), hasmass 3.00mA. A fourth particle D, with mass 4.00mA, is to be placednear the other particles. In terms of distance d, at what (a) x,(b) y, and (c) z coordinate should D be placed so that the netgravitational force on A from B, C, and D is zero?

I found the force for particle D, but i dont know how to get itinto components. The textbook answer uses Dx= D*cosα for x,y,z withdifferent angles for each, but i have no idea how to find thoseangles...

help??

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Elin Hessel
Elin HesselLv2
11 Oct 2019

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