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10 Nov 2019
1) A stepladder (shown in figure 12-52 on page 325 in your book)has sides which are each 3.0m long and hinged at the top. A 0.8mtie-rod is located half way up. A man weighing 800N climbs 2.1malong the ladderâs length. So that weâre all using the samevariables, let us define
W= 800m L=0.3 m d=1.2m s=8.0
Assuming that the floor is frictionless and neglecting the mass ofthe ladder â¦
(0.5 points)
Write an expression for the angle that the ladder makes with thehorizontal.
Model the situation with Newtonâs Second Law [and its rotationalequivalent]. Set up the system of equations as if you were to solvefor the quantities below. You equations should be in terms of thevariables given above only (no numbers) and trig functions of theangle above (just call it ).
One last comment; in addition to the forces below, thereâs one more(your job to figure out what it is) that will be in your equations.The force has components. Tip: Rather than defining a new angle andmessing with more trig functions, just call the x-component Fx andthe y-component Fy in your equations.
solve the above equations for the following quantities (give me anexpression in terms of the variables first, then give me the actualnumber)â¦
(1 points)
a) The tension in the tie-rod. (Call it T in your free-bodydiagrams and equations.)
The magnitude of the force on the ladder from the floor on;
(1 points)
b) the left side of the ladder (where the person is)? (Call it FLin your FBDs and your equations.)
(1 points)
c) the right side of the ladder? (Call it FR in your FBDs and yourequations.)
***Remember to draw free body diagrams (for yourself, not to besubmitted) and write out all equations using variables before youplug in numbers. Also notice that the numbers in your book areslightly different than those in this problem, but the bookâsanswer should provide you a way to check your method andsolution.
1) A stepladder (shown in figure 12-52 on page 325 in your book)has sides which are each 3.0m long and hinged at the top. A 0.8mtie-rod is located half way up. A man weighing 800N climbs 2.1malong the ladderâs length. So that weâre all using the samevariables, let us define
W= 800m L=0.3 m d=1.2m s=8.0
Assuming that the floor is frictionless and neglecting the mass ofthe ladder â¦
(0.5 points)
Write an expression for the angle that the ladder makes with thehorizontal.
Model the situation with Newtonâs Second Law [and its rotationalequivalent]. Set up the system of equations as if you were to solvefor the quantities below. You equations should be in terms of thevariables given above only (no numbers) and trig functions of theangle above (just call it ).
One last comment; in addition to the forces below, thereâs one more(your job to figure out what it is) that will be in your equations.The force has components. Tip: Rather than defining a new angle andmessing with more trig functions, just call the x-component Fx andthe y-component Fy in your equations.
solve the above equations for the following quantities (give me anexpression in terms of the variables first, then give me the actualnumber)â¦
(1 points)
a) The tension in the tie-rod. (Call it T in your free-bodydiagrams and equations.)
The magnitude of the force on the ladder from the floor on;
(1 points)
b) the left side of the ladder (where the person is)? (Call it FLin your FBDs and your equations.)
(1 points)
c) the right side of the ladder? (Call it FR in your FBDs and yourequations.)
***Remember to draw free body diagrams (for yourself, not to besubmitted) and write out all equations using variables before youplug in numbers. Also notice that the numbers in your book areslightly different than those in this problem, but the bookâsanswer should provide you a way to check your method andsolution.
Deanna HettingerLv2
7 Mar 2019
