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10 Nov 2019

Positive charge Q is uniformly distributed around a semicircleof radius a.

((( Since all the X componentscancel, I Thought it would just be (8.988e9)*(Q/C/a^2) with C=2πr/2and i got (8.988e9)*(Q/πa^3) but it was incorrect, i know thecurvature comes in somewhere but im not exactly sure where)))

Find the magnitude of the electric field atthe center of curvature P.
Express your answer in terms of thegiven quantities and appropriate constants.
E = ?N/C

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Trinidad Tremblay
Trinidad TremblayLv2
30 Jul 2019

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