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A proton moving with a speed of 3.0 ח 105 m/s perpendicular to a uniform magnetic field of 0.20 T. What is the radius of the circular path of the proton? (qp = 1.6 × 10-ˆ’19 C and mp = 1.67 × 10-ˆ’27 kg)

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Amal Jeeva
Amal JeevaLv10
22 Jun 2019
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23 Dec 2020

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

An proton (m = 1.67 x 10^-27 kg and q = 1.6 x10^-19 C) travelling at 2.7 × 10^5 ms^-1 enters a magnetic field of 1.2 T at right angles to the direction of motion of the electron. What is the radius of its circular path?

A proton enters a uniform magnetic field with a path perpendicular to the field lines and moves in a circular path of radius . An electron enters the same magnetic field at the same speed in a path perpendicular to the field.
Compared to the protons path, the radius of the electrons circular path is-

(a). Same radius

(b). Large radius

(c). Smaller radius

(d). The electron moves in a straight line.

 

An proton (m = 1.67 x10^-27 kg and q = 1.6 x10^-19 C) travellingat 2.7 × 10^5 ms^-1 enters a magnetic field of 1.2 T at rightangles to the direction of motion of the electron. What is thecentripetal force on the proton?


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