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A motorcyclist who is moving along an x-axis directed toward the east has an acceleration given by a = (6.40 - 2.20t) m/s2 for 0 = t = 6.0 s. At t = 0, the velocity and position of the cyclist are 3.00 m/s and 7.3 m. (a) What is the maximum speed achieved by the cyclist? (b) What total distance does the cyclist travel between t = 0 and t = 6.0 s?

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Rishabh Jain
Rishabh JainLv6
24 May 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

  1. Ā 

    A motorcyclist heading east through a small Iowa city accelerates after he passes the signpost marking the city limits. His acceleration is a constant 4.0 m/S2. At time t = 0 he is 5.0 m east of the signpost, moving east at 15 m/s. (a) find his position and velocity at time t = 2.0 s. (b) Where is the motorcyclist when his velocity is 25 m/s?

2) Vx is the velocity of a particle moving along the x axis asshown. If x = 2.0 m at t = 1.0 s, what is the position of theparticle at t = 6.0 s?


the x-axis is time from 0-6 seconds and the y axis is Vx(m/s^2 and yes this is not a typo thats whats in the book andonline) and it goes from 4 to -2 on the y-axis.
the answer for this problem is -1m as the position at t=6 sbut i am confused because the units of Vx threw me off..isnt m/s^2acceleration? and if its m/s/s then what do i do?

An object moves along the x axis according to theequation x(t) = (4.00t2 - 2.00t+ 3.00) m, where t is in seconds.

(a) Determine the average speed betweent = 3.50 s andt = 5.40 s.
m/s
(b) Determine the instantaneous speed at t = 3.50 s and at t = 5.40 s.
m/s (t = 3.50)
m/s (t = 5.40)
(c) Determine the average acceleration between t =3.50 s and t =5.40 s.
m/s2
(d) Determine the instantaneous acceleration at t =3.50 s and t =5.40 s.
m/s2 (t = 3.50)
m/s2 (t = 5.40)

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