1

answer

0

watching

1,005

views

10 Oct 2018

9.17 - A safety device brings the blade of a power mower from an initial angular speed of w to rest in 1.00 revolution. At the same constant acceleration, how many revolutions would it take the blade to come to rest from an initial angular speed wg that was three times as great, wy = 3w?

word_media_image1.png

1

answer

0

watching

1,005

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Patrina SchowalterLv2

10 Oct 2018

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Related textbook solutions

Physics: Principles with Applications

7th Edition, 2013

ISBN: 9780321625922

Related questions

9.11 .. The rotating blade of a blender turns with constant angu- lar acceleration 1.50 rad/s. (a) How much time does it take to reach an angular velocity of 36.0 rad/s, starting from rest? (b) Through how many revolutions does the blade turn in this time interval?

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At this oint, the person doing the laundry open the lid, and a safety switch turns off the washer. The tub slows to rest in 12.0 s. Thru how many revolutions does the tub trun during the entire 20-s interval? Assume constant angular acceleration while it is starting and stopping.

Use the result (9.73) of Problem 9.26 io do the following: A naval gun shoots a shell at colatitude theta in a direction that is a above the horizontal and due east, with muzzle speed v0. Ignoring the earth's rotation (and air resistance), find how long (l) the shell would be in the air and how far away (R) it would land. If v0 = 500 m/s and alpha = 20degree, what are t and R? A naval gunner sports an enemy ship due east at the range R of part (a) and, forgetting about the Coriolis effect, aims his gun exactly as in part (a). Find by how far north or south, and in which direction, the shell will miss the target, in terms of ohm, v0, alpha, theta, and g. (It will also miss in the east-west direction but this is perhaps less critical.) If the incident occurs at latitude 50degree north (theta = 40degree). What is this distance? What if the latitude is 50degree south? This problem is a serious issue in long-range gunnery: In a battle near the Falkland Islands in World War I, the British navy consistently missed German ships by many tens of yards because they apparently forgot that the Coriolis effect in the southern hemisphere is opposite to that in the north. In Section 9.8, we use a method of successive approximation to find the orbit of an object that is dropped from rest, correct to first order in the earth's angular velocity ohm. Show in the same way that if an object is thrown with initial velocity v0 from a point O on the earth's surface at colatitude theta, then to first order in ohm its orbit is (First solve the equation of motion(9.53) in zeroth) order. that is ignoring ohm entirely. Substitute your zeroth-order solution for and into the right side of equation (9.53) and integrate to give the next approximation. Assume that v0 is small enough that air resistance and that g is a constant throughout the flight) Use the result (9.73) of Problem 9.26 io do the following: A naval gun shoots a shell at colatitude theta in a direction that is a above the horizontal and due east, with muzzle speed v0. Ignoring the earth's rotation (and air resistance), find how long (l) the shell would be in the air and how far away (R) it would land. If v0 = 500 m/s and alpha = 20degree, what are t and R? A naval gunner sports an enemy ship due east at the range R of part (a) and, forgetting about the Coriolis effect, aims his gun exactly as in part (a). Find by how far north or south, and in which direction, the shell will miss the target, in terms of ohm, v0, alpha, theta, and g. (It will also miss in the east-west direction but this is perhaps less critical.) If the incident occurs at latitude 50degree north (theta = 40degree). What is this distance? What if the latitude is 50degree south? This problem is a serious issue in long-range gunnery: In a battle near the Falkland Islands in World War I, the British navy consistently missed German ships by many tens of yards because they apparently forgot that the Coriolis effect in the southern hemisphere is opposite to that in the north.

Related Documents

PHYS 106 Chapter Notes -Circular Motion, Angular Velocity, Angular Acceleration

azurekangaroo166

PHYS 161H Lecture Notes - Lecture 7: Acceleration, Rotation Around A Fixed Axis, Angular Acceleration

amaranthporcupine551

PHYS 100 Chapter Notes - Chapter 10: Gyroscope, Horse Length, Angular Acceleration

Weekly leaderboard

Homework Help 3,900,000

Physics 110,000

Start filling in the gaps now

New to OneClass?Sign up