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18 Dec 2019
A charged particle enters a uniform magnetic field with velocitythat is not perpendicular to the direction of the magnetic field.Find its path of motion in parametric form( with parameter t=time).Assume that the speed of the particle is much smaller than thespeed of light. The force acting on the particle by the magneticfield is F=qv*B, where v=v(x)i+v(y)j+v(z)k is the velocity of thecharge in m/s at any instant, q is the charge in Coulomb, and B isthe magnetic field in Tesla.
A charged particle enters a uniform magnetic field with velocitythat is not perpendicular to the direction of the magnetic field.Find its path of motion in parametric form( with parameter t=time).Assume that the speed of the particle is much smaller than thespeed of light. The force acting on the particle by the magneticfield is F=qv*B, where v=v(x)i+v(y)j+v(z)k is the velocity of thecharge in m/s at any instant, q is the charge in Coulomb, and B isthe magnetic field in Tesla.
jyoti90Lv8
26 Jan 2024
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Hubert KochLv2
31 Dec 2019
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