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1.Calculate the number of moles of PCl5 that can be produced from30.0 of P4 (and excess Cl2 ).
2.Calculate the number of moles of PCl5 that can be produced from53.0 of Cl2 (and excess P4 ).
Then, compare the two values. The reactant that produces thesmaller amount of product is the limiting reactant
1.Calculate the number of moles of PCl5 that can be produced from30.0 of P4 (and excess Cl2 ).
2.Calculate the number of moles of PCl5 that can be produced from53.0 of Cl2 (and excess P4 ).
Then, compare the two values. The reactant that produces thesmaller amount of product is the limiting reactant
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Nelly StrackeLv2
4 Jul 2019
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