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A charged particle in a constant magnetic field B experiences a force f = q(B times upsilon), where upsilon = r' = x'i + y' j + z' k is the velocity vector of the particle. By considering the line integral integral f middot dr, show that this force does no work in moving the particle along its path r(t), 0 lessthanorequalto t lessthanorequalto a, for any a > 0.
A charged particle in a constant magnetic field B experiences a force f = q(B times upsilon), where upsilon = r' = x'i + y' j + z' k is the velocity vector of the particle. By considering the line integral integral f middot dr, show that this force does no work in moving the particle along its path r(t), 0 lessthanorequalto t lessthanorequalto a, for any a > 0.
jyoti90Lv8
26 Jan 2024
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Trinidad TremblayLv2
22 Jan 2019
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