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17 Nov 2019
A charged particle in a constant magnetic field B experiences a force f = q(B à v), where v = r' = x'i + y'i + z'k is the velocity vector of the particle. By considering the line integral f · dr, show that this force does no work in moving the particle along its path r(t), 0 ⤠t ⤠a, for any a > 0 (6) A charged particle in a constant magnetic field B experiences a force f B X v k is the velocity vector of the particle. By considering the line integral J f.dr, show that this force does no work in moving the particle along its path r(t), 0 S t S a, for any a 0.
A charged particle in a constant magnetic field B experiences a force f = q(B Ã v), where v = r' = x'i + y'i + z'k is the velocity vector of the particle. By considering the
line integral f · dr, show that this force does no work in moving the particle along its
path r(t), 0 ⤠t ⤠a, for any a > 0
(6) A charged particle in a constant magnetic field B experiences a force f B X v k is the velocity vector of the particle. By considering the line integral J f.dr, show that this force does no work in moving the particle along its path r(t), 0 S t S a, for any a 0.
jyoti90Lv8
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Reid WolffLv2
16 Jul 2019
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